(i) Find out the charges on the three capacitors connected to a battery as shown in figure. Take C 1 = 1.0 µF, C 2 = 2.0 µF, C 3 = 3.0 µF and V = 20 volt.
(ii) Find out the work done by the battery during the process of charging (initially all the capacitors are uncharged)
(iii) Find out the total energy stored in the capacitors.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
[(i) 20 µC, 40 µC, 60 µC
(ii) 2400 µJ
(iii) 1200 µJ]
Sol.
Q 1 = C 1 V = 1 × 20 = 20 µC
Q 2 = C 2 V = 2 × 20 = 40 µC
Q 3 = C 3 V = 3 × 20 = 60 µC
Q t = 120 µC
W battery = Q t V = 120 × 20 = 2400 µJ
U C = 
C 1 V 2 + 
C 2 V 2 + 
C 3 V 2 = 
(C 1 + C 2 + C 3 )V 2
= 
(1 + 2 + 3) (20) 2 = 1200 µJ.
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