If you have several 2.0 µF capacitors, each capable of withstanding 200 volts without breakdown, how would you assemble a combination having minimum number of capacitors and of given equivalent capacitance which capable of withstanding 1000 volts;
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[ five 2 µF capacitors in series
3 parallel rows; each consisting of five 2.0 µF capacitors in series]
Sol. C eq = 0.4 µF, we connect five 2µF capacitors in series

⇒ C eq =
=
= 0.4 µF
C eq = 1.2 µF, Capable of with standing 1000 volts
3 parallel rows, each consisting of five 2.0 µF capacitors in series.
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