A parallel-plate capacitor of plate area A and plate separation d is charged by a ideal battery of e.m.f. V and then the battery is disconnected. A slab of dielectric constant 2k is then inserted between the plates of the capacitor so as to fill the whole space between the plates. Find the change in potential energy of the system in the process of inserting the slab.
Text Solution
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Sol. Work done on the system = change in potential energy
charge on plate = Q = CV = 
Initial potential energy = 
where C = 
final potential energy = 
where C' = 
Charge in potential energy = final potential energy – initial potential energy,
= 
= 
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