In the figure shown the plates of a parallel plate capacitor have unequal charges. Its capacitance is 'C'. P is a point outside the capacitor and close to the plate of charge – Q. The distance between the plates is 'd'.
A
A point charge at point 'P' will experience electric force due to capacitor
B
The potential difference between the plates will be 
C
The energy stored in the electric field in the region between the plates is 
D
The force on one plate due to the other plate is 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c)
(i) E 0 = 
= 
E in = 
⇒ E in = 
E in = 
⇒ E in d = 
= V
(ii) F = EQ
F = 
× (– Q) = 
F = 
(iii) Energy = 
ε 0 E 2 Ad = 
= 
.
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