Rows of capacitors containing 1,2,4,8,.......... ∞ capacitors, each of capacitance 2F, are connected in parallel as shown in figure. The potential difference across AB = 10 volt, then:
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(a, c)
C = 2µF
C eq = C + 
+ ......
C eq = C 
= 4µF Ans
Charge on first row capacitor is q 1 = 2 × 10µC = 20µC
Charge on second row capacitor is q 2 = 1 × 10µC = 10µC
Charge on third row capacitor is q 3 = 
× 10µC = 5µC
Therefore charge on the capacitor in the first row is more than on any other capacitor.
Energy stored in all capacitor is = 
C eq V 2 = 
× 4 × 10 – 6 × (10) 2 = 0.2 mJ Ans
C = 2µF
C eq = C + 
+ ......
C eq = C 
= 4µF Ans
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