The figure shows a diagonal symmetric arrangement of capacitors and a battery. If the potential of C is zero, then (All the capacitors are initially uncharged).
Text Solution
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(a, b, c, d)
given V C = 0, in AEFC V A – 20 = V C
⇒ V A = 20 V Ans
by KCL, at point D
2 (V A – V D ) + 2 (V B – V D ) + 4 (V C – V D ) = 0
2 (V A – V D ) + 2 (V B – V D ) = 4 V D ..... (i) Ans
by KCL, at point
4 (V A – V B ) + 2 (V D – V B ) + 2 (V C – V B ) = 0
4 (V A – V B ) + 2 (V B – V D ) = 2V B ......(ii) Ans
adding eq (i) and (ii)
2 (V A – V D ) + 2 (V B – V D ) + 4 (V A – V B ) + 2 (V B – V D ) = 4V D + 2 V B
⇒ 6V A = 6 V D + 6V B
⇒ V A = V D + V B
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