Two capacitors of 2 µF & 3 µF are charged to 150 volt & 120 volt respectively. The plates of a capacitor are connected as shown in the fig. A discharged capacitor of capacity 1.5 µF falls to the free ends of the wire and connected through the free ends of the wire, Then:
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c)
V A + 
= V A ..........(i)
by solve this equation we get ⇒ q = 180µC
Charge on 1.5µF capacitor is = 150µC
Charge on 2µF capacitor is = 300 – 180 = 120µC
Therefore charge flows through A from left to right.
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