A parallel plate capacitor of plate area A & plate separation d is charged to a potential difference V & then the battery disconnected. A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively, the magnitude of the charge on each plate, the magnitude of the electric field between the plates (after the slab is inserted) & the magnitude of the work done on the system, in the process of inserting the slab, then:
Text Solution
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(a, c, d)
C = 
, C' = 
Q = CV = 
Ans.
Q = CV = C 1 V 1
⇒ V 1 = 
E = 
Ans.
W = U f – U i = 
CV 2 – 
C 1 V 1 2 = 
= 
Ans.
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