A parallel plate capacitor has a dielectric slab in it. The slab just fills the space inside the capacitor. The capacitor is charged by a battery and the battery is disconnected. Now the slab is started to pull out uniformly at t = 0. If at time t, capacitance of the capacitor is C, potential difference across plate is V, and energy stored in it is U, then which of the following graphs are correct?
Text Solution
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(a, b, c, d)
Capacitance of capacitor is = C 0 = 
C = 
C = 
= 
= 
So, C decreases linearly with time
Charge on capacitor Q = C 0 V 0 = 
V 0 = constant.
Potential difference across plate is
V = 
⇒ V ∝ 
V = 
Potential energy U = 
QV = 
C 0 V 0- V
⇒ U ∝ V Ans
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