Physics Electrostatics Potential & Capacitance JEE (Main) / AIEEE Problems Previous Years - ( Capacitance ) MCQ (Single Correct)

A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volts. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is

A
(K – 1)CV 2
B
CV 2 (K – 1)/K
C
(K – 1)CV 2
D
zero

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
D

Energy stored in parallel plate capacitor of Capacitance C and Potential V is

When the dielectric slab is removed from, between the capacitor energy stored

C is the capacitance in the presence of dielectric
C' is the capacitance in the absence of dielectric and we have where K is the dielectric constant

When the dielectric slab is reinserted the potential energy becomes

Hence the net work done in the process is zero

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.