Let C be the capacitance of a capacitor discharging through a resistor R. Suppose t 1 is the time taken for the energy stored in the capacitor to reduce to half its initial value and t 2 is the time taken for the charge to reduce to one-fourth its initial value. Then the ratio t 1 /t 2 will be
A
1
B
C
D
2
Text Solution
Verified by ExpertsThe correct answer is:
C
U 0 = 
U = 
= 
= 
⇒ 
t 1 = 
ln2 ...
and q = q 0 
= q 0 
,
t 2 = 2τ ln 2 ....
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