Six 1 µF capacitors are so arranged that their equivalent capacitance is 0.70 µF. If a potential difference of 600 volt is applied to the combination, what charge will appear on each capacitor?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(420 µC on one, 180 µC on two, 60 µC on remaining 3 capacitors)
Sol. Equivalent capacitance = 0.7 µF = 
µF
= 
= 
C eq = 0.7µC can be obtain as shown in figure
→ Three capacitors in series
2 → 2 capacitor in parallel.
and now charge distribute as shown in figure
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