A battery of 10 volt is connected to a capacitor of capacity 0.1 F. The battery is now removed and this capacitor is connected to a second uncharged capacitor. If the charge distributes equally on these two capacitors, find the total energy stored in the two capacitors. Further, compare this energy with the initial energy stored in the first capacitor.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
( 
J, 
= 
= 2)
Sol. Q = CV = 0.1 × 10 = 1C
⇒ 
⇒ 
Q 2 = Q 1 = Q/2
U initial = 
× 0.1 × (10) 2 = 5 J
U final = 
+ 
= 
= 
× 10 = 
= 
= 
= 2
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