Two point charges 3 µC and 2.5 µC are placed at point A (1, 1, 2)m and B (0, 3, –1)m respectively. Find out electric field intensity at point C(3, 3, 3)m.
Text Solution
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CHECK THE SOLUTION.
( 
N/C.)
Sol.
r 1 = 
= 
= 3
r 2 = 
= 
= 5
∴ 
= 
= 
. [(3 – 1) 
+ (3 –1) 
+ (3 – 2) 
= 10 3 [2 
+ 2 
+ 
]
= 
= 
. [(3 – 0) 
+ (3 – 3) 
+ {(3 – (–1)} 
]
= 
× 10 3 [3 
+ 0 
+ 4 
]
= 
× 1000 [ 3 
+ 4 
] = 180 [3 
+ 4 
]
∴ 
= 
+ 
= [2000 
+ 2000 
+ 1000 
] + [540 
+ 720 
]
= [2540 
+ 2000 
+ 1720 
] N/C.
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