The bob of a simple pendulum has a mass of 60 g and a positive charge of 6 × 10 –6 C. It makes 30 oscillations in 50 s above earth's surface. A vertical electric field pointing upward and of magnitude 5 × 10 4 N/C is switched on. How much time will it now take to complete 60 oscillations? (g = 10 m/s 2 )
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(100 
≈ 141s)
Sol. (1) Time period in the absence of field
T = 
(2) When electric field is switched on;
g eft = g – 
= 10 – 
= 5 m/s 2
(3) ∴ New time period T' = 
= 
(4) Let time taken to complete 60 oscillations is t 0 .
T' = 
or t o = T' × 60 = 100 
≈ 141s
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