Two positive point charges 15 µC and 10 µC are 30 cm apart. Calculate the work done in bringing them closer to each other by 15 cm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(4.5 J)
Sol. By energy conservation between initial and final state of the system
W + (K.E) 1 + (P.E) 1 = (K.E) 2 + (P.E) 2
W + 0 + 
= 0 + 
or, W = kq 1 q 2 
W = 9 × 10 9 × 15 × 10 –6 × 10 × 10 –6 
∴ W = 4.5 Joule
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Three point charges are arranged at the three vertices of a triangle as shown in Figure. Given: q =…
Eight equal point charges each of charge 'q' and mass 'm' are placed at eight corners of a cube of …
Six charges of magnitude + q and –q are fixed at the corners of a regular hexagon of edge length a …