Six charges of magnitude + q and –q are fixed at the corners of a regular hexagon of edge length a as shown in the figure. The electrostatic potential energy of the system of charged particles is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
⇒ 
E.P.E. of charge +q at point A can be given as:
E A = 
+ 
– 
& E.P.E. of system
⇒ E S = 
where E A = E B = E C = E D = E E = E F
∴ E S = 3 E A
∴ E S = 
+ 6 
+ 3 
= 
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