A charge q is placed at the center of an imaginary hemispherical surface. Using symmetry arguments and the Gauss’s law, find the electric flux due to this charge through the given surface.

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
q/(2ε 0 )
Sol.

Let us complete the sphere by drawing remaining hemisphere dotted as shown in
Then total electric flux through complete sphere.
=
= φ φ
Hence flux through lower hemisphere ⇒
= 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinde…
Electric field at a point varies as for
An electric charge q is placed at the center of a cube of side α. The electric flux on one of its f…
Total electric flux coming out of a unit positive charge put in air is
For a given surface the Gauss's law is stated as . From this we can conclude that
A cube of side l is placed in a uniform field E, where . The net electric flux through the cube is