In the arrangement shown, the pendulum on the left is pulled aside. It is then released and allowed to collide with other pendulum which is at rest. A perfectly inelastic collision occurs and the system rises to a height h/4 . The ratio of the masses (m 1 / m 2 ) of the pendulum is :
Text Solution
Verified by ExpertsThe correct answer is:
A
+ 0 = (m 1 + m 2 ) v
v = 
∴ v 2 – u 2 + 2g × 
= 6 + 2g × 
= 
∴ v = 
Also, 
= 
⇒ 2m 1 + m 1 + m 2 ∴ 
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