Published by:
CGP EDU Academic Team
Published on: September 12, 2026
There are hundred identical sliders equally spaced on a frictionless track as shown in the figure. Initially all the sliders are at rest. Slider 1 is pushed with velocity v towards slider 2. In a collision the sliders stick together. The final velocity of the set of hundred stucked sliders will be :

Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Understand the situation. There are 100 identical sliders, all at rest except slider 1, which moves with velocity v.
Step 2: Use conservation of momentum. Before the collision, only slider 1 has momentum, given by \(P_{initial} = m v\), where \(m\) is the mass of one slider.
Step 3: After the collision, all sliders are stuck together and move with a common velocity \(V_f\). The total mass after collision is \(100m\). Therefore, momentum after collision is \(P_{final} = (100m) V_f\).
Step 4: Setting initial momentum equal to final momentum:
\(m v = (100m) V_f\)
Step 5: Cancelling mass \(m\) from both sides gives:
\(v = 100 V_f\).
Step 6: Rearranging gives: \(V_f = \frac{v}{100}\). Thus the correct answer is option A.
Step 2: Use conservation of momentum. Before the collision, only slider 1 has momentum, given by \(P_{initial} = m v\), where \(m\) is the mass of one slider.
Step 3: After the collision, all sliders are stuck together and move with a common velocity \(V_f\). The total mass after collision is \(100m\). Therefore, momentum after collision is \(P_{final} = (100m) V_f\).
Step 4: Setting initial momentum equal to final momentum:
\(m v = (100m) V_f\)
Step 5: Cancelling mass \(m\) from both sides gives:
\(v = 100 V_f\).
Step 6: Rearranging gives: \(V_f = \frac{v}{100}\). Thus the correct answer is option A.
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