A bullet fired horizontally with a speed of 400 m/sec. It strikes a wooden block of mass 5 kg initially at rest placed on a horizontal floor as shown in the figure. It emerges with a speed of 200 m/sec and the block slides a distance 20 cm before coming to rest. If the coefficient of friction between block and the surface is 
then find λ . Mass of bullet is 20 gm. (take g = 10 m/s 2 )
Text Solution
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(8)
m = 20 × 10 –3 kg ; M = 5 kg
u = 400 d = 0.2 m
V = 200 μ = ?
Δ P Bullet = Δ P Block
m (u – v) = 20×10 –3 (400 – 200) = 4 kg. m/s.
KE Block = 
= 
= 1.6 J = μ Mgd
μ = 
= 
= 0.16
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