A particle A of mass 2kg lies on the edge of a table of height 1m. It is connected by a light inelastic string of length 0.7m to a second particle B of mass 3kg which is lying on the table 0.25m from the edge (line joining A & B is perpendicular to the edge). If A is pushed gently so that it starts falling from table. After some time string becomes tight. If the impulse of the tension in the string at that moment is 3 λ /5 then find λ . Assume all contacts are smooth. g = 10 m/s 2
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(6)
string will taut when A waves a distance of (.7 – .25) m
at that Pt V A = 
and Now B starts on using with same velocity as A.
let us suppose it is u.
= m B u + 0 ....(1)
– 
= m A (u –V A ) ....(2)
from (1) and (2) u = 
= 
u = 
= 
∴ 
= 3.6 N-s
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