A block of mass 2 kg moving at 2.0 m/s collides head on with another block of equal mass kept at rest. If the loss in kinetic energy of system is half of the maximum possible loss of kinetic energy of system , If the coefficient of restitution 
. then find λ .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(1)
M = 2kg , u = 2m/sec.
Max loss in K.E. means e = 0
K.E. e = 0
mu = 2mV ∴ V = 
Loss = K i – K f
= 
mu 2 – 
(2m) V 2 = 
mu 2 = 
× 2 × (2) 2 = 2 J
If loss = 1 J = 
mu 2 = 
Reamaining K.E. = 
mu 2 = 
mu 2 (finally)
coeff of restitution e = 
∴ V 2 – V 1 = eu ....(1)
By momentum conservation
mu = mV 1 + mV 2
u = V 1 + V 2 .....(2)
∴ V 2 = 
× u
∴ V 1 = 
× u
mV 1 2 + 
mV 2 2 = 
mu 2 ......(3)
+ 
= 
u 2
2 + 2 e 2 = 3 ∴ e = 
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