A hemisphere S and a particle P are of same mass m = 
kg. P is dropped from a height ‘h’. S is kept on a smooth horizontal surface. The friction between P and S is also absent. P collides elastically with S at the point shown in the figure. After collision the velocity of the particle becomes horizontal. Find ratio of impulse of ground on hemisphere to speed of hemisphere after collision ?
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(2)
when particle P starts at Pt A u = 
u = 
1 = 
....(i)
Now applying momentum conservation equ.
m × V 1 = mV 2 ∴ V 1 = V 2 ...(2)
using ME.C ⇒ mgh = 
m V 1 2 + 
m V 2 2 ...(3)
as solving V 1 = 
on solving alone (3) equ. we get tan θ = 
tan θ = 
Impulse of ground on hemisphere.
J = m.u = m. 
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