A ball of mass 0.2 kg rests on a vertical post of height 5 m. A bullet of mass 0.01 kg, traveling with a velocity V m/s in a horizontal direction, hits the centre of the ball. After the collision, the ball and bullet travel independently. The ball hits the ground at a distance of 20 m and the bullet at a distance of 100 m from the foot of the post. The initial velocity V of the bullet is
m/s
Text Solution
Verified by ExpertsD
R = 
⇒ 20 = 
and 100 = 
⇒ V 1 = 20 m/s , V 2 = 100 m/sec.
Applying momentum conservation just before and just after the collision
(0.01) (V) = (0.2)(20) + (0.01)(100) ⇒ V = 500 m/s
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems