It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional loss of its energy is p d , while for its similar collision with carbon nucleus at rest, fractional loss of energy is p c . The values of p d and p c are respectively :
Text Solution
Verified by ExpertsThe correct answer is:
C
Case-I
JBC
JAC
2V 2 – V 1 = V
V 2 + V 1 = V
3V 2 = 2V
V 2 = 
V 1 = 
P d = 
= 0.89
Case-II
JBC
JAC
12V 2 – V 1 = V
V 2 + V 1 = V
13V 2 = 2V
V 2 = 
V 1 = V – 
⇒ P c = 
= 0.28
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