Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A train is moving slowly on a straight track with a constant speed of . A passenger in that train starts walking at a steady speed of
to the back of the train in the opposite direction of the motion of the train. So to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be
A
B
C
D
zero
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Let the speed of the train be \( v_t \) and the speed of the passenger be \( v_p \). Since the passenger is walking in the opposite direction to the motion of the train, the relative speed of the passenger with respect to the observer on the platform will be the speed of the train minus the speed of the passenger.
Step 2: The velocity of the passenger with respect to the ground is given by:
\[ v_{relative} = v_t - v_p \]
Step 3: Since both speeds are towards opposite directions, to the observer on the platform, the passenger moves at a speed equal to the difference between the speed of the train and the speed of the passenger if the passenger is moving backwards with respect to the train.
Therefore, the final answer is \( v_t - v_p \) which is represented in option A.
Step 2: The velocity of the passenger with respect to the ground is given by:
\[ v_{relative} = v_t - v_p \]
Step 3: Since both speeds are towards opposite directions, to the observer on the platform, the passenger moves at a speed equal to the difference between the speed of the train and the speed of the passenger if the passenger is moving backwards with respect to the train.
Therefore, the final answer is \( v_t - v_p \) which is represented in option A.
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