Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A Spherical ball of radius 1mm and density 10.5 g/cc is dropped in glycerine of coefficient of viscosity 9.8 poise and density 1.5 g/cc. Viscous force on the ball when it attains constant velocity is 3696 x 10 -x N. The value of x is (Given, g = 9.8 m/s 2 and
)
Text Solution
Verified by ExpertsThe correct answer is:
7
(7)
When the ball attain terminal velocity
F v =(mg-F B )(va = 0)
= V
b g-V
g
= Vg(
b -
)
=
(10 -3 ) 3 x9.8(10.5-1.5) x10 3
= 3696x10 -7 N
So, x=7
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