Home Physics Atomic and Nuclear Physics JEE Main 2023 - ( Atomic Physics ) Nucleus a having Z = 17 and equal number of …
Physics Atomic and Nuclear Physics JEE Main 2023 - ( Atomic Physics ) MCQ (Single Correct)

Nucleus a having Z = 17 and equal number of protons and neutrons has L2 MeV binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be____MeV.

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CHECK THE SOLUTION.

(6)

Total binding energy = 1.2 x 34 = 40.8 MeV

For B mass number = 26

total binding energy = 1.8 x 26 MeV = 46.8 MeV

Difference of BE = 6 MeV

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