Nucleus a having Z = 17 and equal number of protons and neutrons has L2 MeV binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be____MeV.
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(6)
Total binding energy = 1.2 x 34 = 40.8 MeV
For B mass number = 26
total binding energy = 1.8 x 26 MeV = 46.8 MeV
Difference of BE = 6 MeV
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