Energy released when two deuterons
fuse to form a helium nucleus
is:
(Given: Binding energy per nucleon of
and binding energy per nucleon of
)
Text Solution
Verified by ExpertsC
To calculate the energy released when two deuterons (
) fuse to form a helium nucleus
, consider the following:
The reaction is represented as:

Given the binding energy per nucleon:
For
For
Calculating Binding Energy
Binding Energy for Reactants:
Each deuteron (
) has a binding energy of 1.1 MeV per nucleon.
Since there are two nucleons in a deuteron, the total binding energy for one deuteron is
.
Therefore, for two deuterons:

Binding Energy for Product:
For
: Each of the four nucleons has a binding energy of 7.0 MeV.
Total binding energy for the helium nucleus:

Energy Released (Q)
The energy released, Q, is the difference between the binding energy of the products and the reactants:

Thus, the energy released when two deuterons fuse to form a helium nucleus is 23.6 MeV.
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