A 0.60 kg sample of water and a sample of ice are placed in two compartments A and B that are separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice though the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the compartments remain homogeneous during whole heat transfer process.
Given specific heat of ice = 2100 J/kg-K
Given specific heat of water = 4200 J/kg-K
Latent heat of fusion of ice = 3.3 × 10 5 J/kg
(i) The value of rate P is
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) : In 40 min. temperature of water has come down by 40°C.
Therefore, rate P = 
= 
= 42.0 W
(ii) : Sample of ice has been receiving heat at constant rate P from water. Its temperature has
increased by 30°C in time 60 min.
Therefore 
= 60 min.
m = 
= 2.4 kg
(iii) : Thermal equilibrium reaches after 60 min. Ice conversion takes place for 20 min. During this
time water at 0°C continues to give heat at rate P.
m × L f = P × (20 × 60s)
m = 
kg = 0.15 kg
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