In an insulated vessel, 0.05 kg steam at 373 K and 0.45 kg of ice at 253 K are mixed. Find the final temperature of the mixture (in Kelvin).
Given, L fusion = 80 cal/gm = 336 J/gm, L vaporization = 540 cal/gm = 2268 J/gm, S ice = 2100 J/kg K = 0.5 cal/gm K and S water = 4200 J/kg K = 1 cal/gmK
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(273 K)
Sol. ΣΔ Q = 0
Heat lost by steam to convert into 0ºC water
H L = 0.05 × 540 + 0.05 × 100 × 1
= 27 + 5 = 32 kcal
Heat required by ice to change into 0º C water
H g = 0.45 × 
× 20 + 0.45 × 80 = 4.5 + 36.00 = 40.5 kcal
Thus, final temperature of mixture is 0ºC = 273 K
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