A metal piece weighing 15g is heated to 100ºC and then immersed in a mixture of ice and water at the thermal equilibrium. The volume of the mixture is found to be reduced by 0.15 cm 3 with the temperature of mixture remaining constant. Find the specific heat of the metal. Given specific gravity of ice = 0.92, latent heat of fusion of ice = 80 cal/gm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(0.092 cal/gmºC)
Sol. 
= 0.15
m = 
∴ H lost = H gained
15 × S × 100 = 
S = 0.092 cal/gmºC.
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