A piece of metal weighs 46 g in air. When it is immersed in a liquid of specific gravity 1.24 at 27º C it weighs 30 g. When the temperature of liquid is raised to 42º C the metal piece weighs 30.5 g. Specific gravity of liquid at 42º C is 1.20. Calculate the coefficient of linear expansion of the metal.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(α = 
/º C = 2.31 × 10 -5 /º C)
Sol. W 0 = mg = 46 g wt
at θ 1 = 27º C
W 1 = 30 gm wt = W 0 – B 1
⇒ B 1 = (46 – 30) gm
⇒ B 1 = 16gm wt = V 1 ρ 1 g
at θ 2 = 42º C
W 2 = 30.5 g wt = W 0 – B 2
⇒ B 2 = 15.5 gm wt = V 2 ρ 2 g
∴ 
= 
= (1 + 3 α s × 15) × 
α s = 
α s = 2.31 × 10 –5 /ºC = 
/ ºC Ans
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