Two identical rings which can slide along the rod are kept near the mid point of a smooth rod of length 2 
( 
= 1 m) The rod is rotated with constant angular velocity 
= 3 radian/ sec about vertical axis passing through its center. The rod is at height h = 5 m from the ground. Find the distance (in meter) between the points on the ground where the rings will fall after leaving the rods
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(10 m)
Sol. Time take by ring to fall on ground.
T = 
from centripetal force
m ω 2 x = ma = mv 
ω 2 x = v 
v x = ω L
x = ω λ . T = ω λ 
v y = ω L
y = ω λ T = ω λ 
distance of one ring from center is
= 
distance between the point on the ground where the rings will fall after leaving the rods.
= 2 
where x = y = ω λ 
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