Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A battery sets up an electric field of 25 N/C inside a uniform wire of length 2 m and a resistance of 5 Ω Ω . Find current through the wire.
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Calculate the voltage (V) across the wire using the formula for electric field (E) and length (L):
\[ V = E \times L = 25 \text{ N/C} \times 2 ext{ m} = 50 ext{ V} \]
Step 2: Use Ohm's Law (V = I \times R) to find the current (I), where V is the voltage, I is the current, and R is the resistance:
\[ I = \frac{V}{R} = \frac{50 ext{ V}}{5 \Omega} = 10 ext{ A} \]
Therefore, the current through the wire is 10 A.
\[ V = E \times L = 25 \text{ N/C} \times 2 ext{ m} = 50 ext{ V} \]
Step 2: Use Ohm's Law (V = I \times R) to find the current (I), where V is the voltage, I is the current, and R is the resistance:
\[ I = \frac{V}{R} = \frac{50 ext{ V}}{5 \Omega} = 10 ext{ A} \]
Therefore, the current through the wire is 10 A.
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