A uniform string of mass ‘M’ and length 2a, is placed symmetrically over a smooth and small pulley and has particles of masses ‘m’ and ‘m’’ attached to its ends; show that when the string runs off the peg its velocity is 
. Assume that m > m’.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
– g [ma + ma + M 
] = – g [ m2a + m´0 + Ma] + 
(M + m + m) v 2
= v
v = 
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