In the figure the variation of potential energy of a particle of mass m = 2kg is represented w.r.t. its x-coordinate. The particle moves under the effect of this conservative force along the x-axis.
(i) If the particle is released at the origin then:
Text Solution
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(i) If the particle is released at the origin, it will try to go in the direction of force. Here 
is positive and hence force is negative, as a result it will move towards – ve x-axis.
(ii) When the particle is released at x = 2 + 
it will reach the point of least possible potential energy
(–15 J) where it will have maximum kinetic energy.
= 25
v max = 5 m/s
(iii)
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