In the fig. the potentiometer wire AB of length L & resistance 9 r is joined to the cell D of e.m.f. ε & internal resistance r. The cell C's e.m.f. is ε /2 and its internal resistance is 2 r. The galvanometer G will show no deflection then find length AJ:
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(5L/9)
Sol. Current in primary circuit. I = 
Potential drop across length AB
AB = V AB = I.R
V AB = 
= 
, x = 
For balance point 
= x λ = 
λ .
λ = 
L
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