In the network shown, points A, B and C are potentials of 7…

Physics Current Electricity General MCQ (Single Correct)

In the network shown, points A, B and C are potentials of 70 V, zero and 10 V respectively.

Point D is at a potential of 40 V

The currents in the sections AD, DB, DC are in the ratio 3: 2: 1

The currents in the sections AD, DB, DC are in the ratio 1: 2: 3

The network draws a total power of 200 W.

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(a, b, d)

Let potential of point D is x. by KCL at point D.

I 1 + I 2 + I 3 = 0

+ + = 0

⇒ 6x – 420 + 3x + 2x – 20 = 0

⇒ 11x = 440

⇒ x = 40 volt

∴ I 1 = = – 3A, I 2 = = 2A

I 3 = = 1A

P = i 2 R

P = 3 2 × 10 + 2 2 × 20 + 1 2 × 30

P = 200 W

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