A

Step 1: To convert the galvanometer into an ammeter, we need to calculate the shunt resistance required to bypass a portion of the current.
The galvanometer has a current sensitivity of 20 µA/div and 30 divisions, so the full-scale deflection (FSD) current, $I_g$, is given by:
$$I_g = 30 imes 20 imes 10^{-6} A = 0.0006 A = 0.6 mA$$
For the ammeter to read up to 1 A, we will need to pass 1 A through the ammeter.
Step 2: The shunt current ($I_s$) that would bypass the galvanometer can be calculated as:
$$I_s = I - I_g = 1 A - 0.0006 A = 0.9994 A$$
Step 3: We can now use the shunt resistance formula:
$$R_s = rac{V_g}{I_s}$$
where $V_g$ is the voltage across the galvanometer. The voltage across the galvanometer can be calculated using Ohm's law:
$$V_g = I_g imes R_g = 0.0006 A imes 25 ext{ ohm} = 0.015 V$$
Now substituting the values:
$$R_s = rac{0.015 V}{0.9994 A} \approx 0.01501 ext{ ohm}$$
This is the shunt resistance required to convert the galvanometer into an ammeter measuring up to 1 A.
Step 4: To convert the ammeter into a voltmeter reading up to 1 V, we will need to connect a series resistance ($R_v$) to the ammeter. The total voltage across the ammeter when it shows full-scale deflection has to be set to 1 V. Using Ohm's law:
$$V = I imes R$$
The maximum current through the circuit when the ammeter is measuring full scale is still 1 A:
$$1V = 1A imes (R_g + R_v)$$
We already have $R_g = 25 ext{ ohm}$, thus:
$$R_v = rac{1V}{1A} - R_g = 1 - 25 = -24 ext{ ohm}$$
Since negative resistance is not possible, we cannot convert this ammeter to voltmeter accurately up to 1 V with this setup. Thus, the procedure for conversion to ammeter is successful but the voltmeter conversion is not possible with the provided galvanometer.
Therefore, to summarize, the ammeter can be achieved with shunt resistance approximately 0.015 ohm, but the conversion to the voltmeter to read 1 V is not feasible.