When a cell is connected in a circuit, a current I 1 flows in the circuit. When one more identical cell is connected in series with the first one, a current I 2 is found to flow in the circuit. When same cell is connected in parallel with the first one, the current is found to be I 3 . Show that:3 I 2 I 3 = 2 I 1 (I 2 + I 3 ).
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
I 1 = 
r + R = 
I 2 = 
2r + R = 
I 3 = 
= 
To show that 3 I 2 I 3 = 2I 1 (I 2 + I 3 )
L.H.S = 3 × 
× 
= 2 
= R.H.S
3E = 
3r + 3R = r + 2R + 2r + R
Hence its prove.
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