The heavier block in an Atwood machine has a mass twice that of the lighter one. The tension in the string is 16.0 N when the system is set into motion. Find the decrease in the gravitational potential energy during the first second after the system is released from rest.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(2 g = 19.6 J)
Sol. Let m 1 = 2m 2
a = 
= 
g = g/3
So, distance travelled by each block = 
at 2 = g/6
Also, T = 
= 
= 16
m 2 = 
Hence, loss in gravitation P.E. during first second = (m 1 – m 2 ) gh
= (2m 2 – m 2 ) g × 
= 
= 2g.
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