In the figure a block slides along a track from one level to a higher level, by moving through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block’s initial speed v 0 is 6m/s, the height difference h is 1.1 m and the coefficient of kinetic friction µ is 0.6. The value of d is:
Text Solution
Verified by ExpertsThe correct answer is:
A
W f + W G = 
K
– μ mgd – mgh = 0 – 
m v 0 2
μ gd + gh = 
(v 0 2 )
(0.6) (10) d + 10(1.1) = 18
d = 
= 1.1666 
1.17m
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