A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The velocity of the block at the bottom will be -
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Energy conservation between
point A & B
K.E. + P.E.) A = (K.E. + P.E.) B
0 + 0 = 
mv 2 – mgR
V = 
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