A piece of wood of mass 0.03 kg is dropped from the top of a 100 m height building. At the same time a bullet of mass 0.02 kg is fired vertically upwards, with a velocity 100 ms –1 from the ground. The bullet gets embedded in the wood. Then the maximum height to which the combined system reaches above the top of the building before falling below is : (g = 10 m/s –2 )
Text Solution
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a rel = 0
v rel = 100
100 = v rel × t
t = 
= 1 sec
v bullet = 100 – 1 × 10
= 90 m/s
v particle = 10 × 1 = 10 m/s
S = 100 × 1 – 1/2 × 10 × 1 = 95 m
P i = P f
= 90 × 0.02 – 10 × 0.03 = 0.05V
V = 30 m/s
h = 
= 45 m
so from top of tower
45 – 5 = 40 m
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