Three blocks A, B and C are lying on a smooth horizontal surface, as shown in the figure. A and B have equal masses, m which C has mass M. Block A is given an initial speed v towards B due to which it collides with B perfectly inelastically. The combined mass collides with C, also perfectly inelastically 
of the initial kinetic energy is lost in whole process. What is value of M/m ? 
Text Solution
Verified by ExpertsThe correct answer is:
B
mv = (2m + M)v'
v' = 
Initial energy Final energy
= 
4m = M
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