Trajectory of particle in a projectile motion is given as . Here, x and y are in meter. For this projectile motion match the following with . Column IColumn II(A)Angle of projectionI.20 m(B)Angle of velocity with horizontal after 4 sII.80 m(C)Maximum heightIII.(D)Horizontal rangeIV. Choose the correct answer from the options given below.

Trajectory of particle in a projectile motion is given as …

Physics Motion in a Plane Matching Type Question MCQ (Single Correct)

Trajectory of particle in a projectile motion is given as . Here, x and y are in

meter. For this projectile motion match the following with .

Column I	Column II
(A)	Angle of projection	I.	20 m
(B)	Angle of velocity with horizontal after 4 s	II.	80 m
(C)	Maximum height	III.
(D)	Horizontal range	IV.

Choose the correct answer from the options given below.

A-IV, B-II, C-III, D-I

A-III, B-IV, C-II, D-I

A-I, B-III, C-IV, D-II

A-III, B-IV, C-I, D-II

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The correct answer is:

Comparing with the standard equation of Projectile,

We get, and
Time period of this projectile is 4 s. Hence, After 4 s, Velocity vector will again make an angle of with horizontal.
So, maximum height,

and horizontal range,

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