Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Study the following
graphs is Column I carefully and match appropriately with the
statements given in Column II. Assume that motion takes place from time 0 to
.
Column I | Column II | ||
(A) | (I) | Net displacement is positive, but not zero | |
(B) | (II) | Net displacement is negative, but not zero | |
(C) | (III) | Particle returns to its initial position again | |
(D) | (IV) | Acceleration is positive |
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: Identify the graphs from Column I:
(A) indicates a graph with positive net displacement (e.g., moving forward).
(B) indicates a graph with negative net displacement (e.g., moving backward).
(C) indicates a graph where the particle returns to its initial position (zero displacement).
(D) indicates a graph with constant positive acceleration.
Step 2: Analyze the statements in Column II:
I: Net displacement is positive but not zero → Matches A
II: Net displacement is negative, but not zero → Matches B
III: Particle returns to its initial position → Matches C
IV: Acceleration is positive → Matches A
Step 3: Matching:
A → I, IV; B → II; C → III
D is not matched. Therefore, the matching is A-I and IV, B-II, C-III; thus, the answer is C.
(A) indicates a graph with positive net displacement (e.g., moving forward).
(B) indicates a graph with negative net displacement (e.g., moving backward).
(C) indicates a graph where the particle returns to its initial position (zero displacement).
(D) indicates a graph with constant positive acceleration.
Step 2: Analyze the statements in Column II:
I: Net displacement is positive but not zero → Matches A
II: Net displacement is negative, but not zero → Matches B
III: Particle returns to its initial position → Matches C
IV: Acceleration is positive → Matches A
Step 3: Matching:
A → I, IV; B → II; C → III
D is not matched. Therefore, the matching is A-I and IV, B-II, C-III; thus, the answer is C.
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