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CGP EDU Academic Team
Published on: September 12, 2026
Find the equation of straight line for the following figure.

Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Identify the points on the graph.
The line passes through two points: (0, 5) and (4, 0).
Step 2: Calculate the slope (m) of the line.
The slope is given by the formula:
$$ m = \frac{y_2 - y_1}{x_2 - x_1} $$
Here, (x1, y1) = (0, 5) and (x2, y2) = (4, 0). So,
$$ m = \frac{0 - 5}{4 - 0} = \frac{-5}{4} $$
Step 3: Use point-slope form to find the equation.
The point-slope form of the equation of a line is:
$$ y - y_1 = m(x - x_1) $$
Substituting m = -5/4, (x1, y1) = (0, 5):
$$ y - 5 = -\frac{5}{4}(x - 0) $$
Simplifying this leads to:
$$ y - 5 = -\frac{5}{4}x $$
Thus,
$$ y = -\frac{5}{4}x + 5 $$
Step 4: Rearranging the equation.
Multiply through by 4 to eliminate the fraction:
$$ 4y = -5x + 20 $$
Or:
$$ 5x + 4y - 20 = 0 $$
Therefore, the equation of the straight line is: $$ 5x + 4y - 20 = 0 $$.
The line passes through two points: (0, 5) and (4, 0).
Step 2: Calculate the slope (m) of the line.
The slope is given by the formula:
$$ m = \frac{y_2 - y_1}{x_2 - x_1} $$
Here, (x1, y1) = (0, 5) and (x2, y2) = (4, 0). So,
$$ m = \frac{0 - 5}{4 - 0} = \frac{-5}{4} $$
Step 3: Use point-slope form to find the equation.
The point-slope form of the equation of a line is:
$$ y - y_1 = m(x - x_1) $$
Substituting m = -5/4, (x1, y1) = (0, 5):
$$ y - 5 = -\frac{5}{4}(x - 0) $$
Simplifying this leads to:
$$ y - 5 = -\frac{5}{4}x $$
Thus,
$$ y = -\frac{5}{4}x + 5 $$
Step 4: Rearranging the equation.
Multiply through by 4 to eliminate the fraction:
$$ 4y = -5x + 20 $$
Or:
$$ 5x + 4y - 20 = 0 $$
Therefore, the equation of the straight line is: $$ 5x + 4y - 20 = 0 $$.
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